sebuah fungsi dinyatakan dengan rumus g(x) = ax + b jika g (3) = -5 dan g(-2) = 10, maka g(5) + g(2) =

g(x) = ax + b
g(3) = -5
g(-2) = 10
g(5) + g(2) = ?

g(3) = -5
a(3) + b = -5
3a + b = -5 ....(1)

g(-2) = 10
a(-2) + b = 10
-2a + b = 10 ....(2)

eliminasi (1) dan (2)
3a + b = -5
-2a + b = 10
_________ -
5a = -15
a = -15/5 = -3

masukkan a = -3 ke (1)
3(-3) + b = -5
-9 + b = -5
b = -5 + 9 = 4

g(x) = ax + b, dengan a = -3 dan b = 4
g(x) = -3x + 4

g(5) + g(2)
= -3(5) + 4 + (-3)(2) + 4
= -15 + 4 - 6 + 4
= -13

maaf kalau salah
semoga membantu