Fisika

Pertanyaan

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1 Jawaban

  • F2x = F2 cos a
    F2x = 100 - cos 60°
    F2x = 100 . -1/2
    F2x = -50 N

    F2y = F2 sin a
    F2y = 100 sin 60
    F2y = 100 . 1/2 √3
    F2y = 50√3 N

    F3x = F3 cos a
    F3x = 100 - cos 60
    F3x = 100 . - 1/2
    F3x = -50 N

    F3y = F3 sin a
    F3y = 100 - sin 60
    F3y = 100 .- 1/2 √3
    F3y = -50√3 N

    Fx = F1 + F2x + F3x
    Fx = 50 - 50 - 50
    Fx = - 50 N

    Fy = F2y + F3y
    Fy = 50√3 - 50√3
    Fy = 0

    F = √Fx² + Fy²
    F = √-50² + 0²
    F = √2500
    F = 50 N

    jawaban : b