Bantu yaaa,, pakai caraa

a. garis g yang melalui titik (3,-6) dan sejajar 3y - 4x + 6 = 0
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3y - 4x + 6 = 0
3y = 4x - 6
  y = (4/3)x - 2  >> m=(4/3)
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Pers. garis g adalah
y + 6 = (4/3)(x - 3)
y = (4/3)x - 4 - 6
y = (4/3)x - 10
3y - 4x + 10 = 0


b. garis h yang melalui titik (3,-2) dan tegak lurus 3y - 2x + 3 = 0
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3y - 2x + 3 = 0
3y = 2x - 3
  y = (2/3)x - 1  >> m=(2/3)
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garis h tegak lurus dengan garis y = (2/3)x - 1, maka gradien garis h adalah
-(3/2)
Sehingga pers. garis h
y + 2 = -(3/2)(x - 3)
y = -(3/2)x + 9/2 - 2
y = -(3/2)x + 5/2
y = (-3x + 5) / 2
2y = -3x + 5
2y + 3x - 5 = 0


c. garis L melalui titik (-2,4) dan tegak lurus garis k yang melalui titik (-5,6) dan (9,1)
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gradien garis k
m = (y2-y1) / (x2-x1)
m = (6 -1) / (-5 - 9)
m = -(5/14)
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karena garis L tegak lurus garis k, maka gradien garis k adalh
m = (14/5)
Pers. garis k
y - 4 = (14/5)(x + 2)
y = (14/5)x + 28/5 + 4
y = (14/5)x + 48/5
y = (14x + 48) / 5
5y - 14x - 48 =0