1.Jika f(x) =x^5-mx^4-2x^3+x+1 dan f(2)=3 maka nilai f(-2) = 2. Dia suku banyak memenuhi f(x)=x^3-4x^2+5x+p dan g(x)=x^2+3x+2. Jika f(-1)=g(1) maka nilai p sam

1) f(x) = x^5 - mx^4 - 2x^3 - x + 1. f (2) = 3
==» 2^5 - m(2)^4 - 2(2)^3 - 2 +1 = 3
==» 32 - 16 m - 16 -2 + 1 = 3
==» - 16 m + 15 = 3
==» - 16 m = -12
==» m = 3/4
Jadi f(x) = x^5 -3/4x^4 - 2x^3 -x + 1
f(-2) = (-2)^5 -3/4(-2)^4 -2(-2)^3 - -2 +1
= -32 -12 +16 + 2 +1
= 19 - 42
= -23
2) f(-1) = (-1)^5 -4(-1)^2 +5(-1) + p
= -1 - 4 - 5 + p
= p - 10
g(1) = (1)^2 + 3.1 +2
= 1 +3 +2
= 6
f(-1) = g(1)
P - 10 = 6
p = 6 +10
p = 16
3) f (x) - g (x)
= ( x^3 - x^2 + 12 ) - ( x^3 - 10 )
= x^3 - x^2 + 12 - x^3 + 10
= -x^2 + 22