selesaikan persamaan logaritma berikut x¹ + x log 16 = 4x²
Matematika
panji461
Pertanyaan
selesaikan persamaan logaritma berikut x¹ + x log 16 = 4x²
1 Jawaban
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1. Jawaban opangunnie
x(1+log 16)=4x^2
x(1+ log 16)=4x^2
1+log 16= 4x^2/x
log 16= 4x-1
log 2^4=4x-1
4.log 2 = 4x-1
log 2 = 4x-1/4
0,301=4x-1/4
1,204=4x-1
2,204=4x
x=2,204/4=0,551