diketahui 2'log 5= X DAN 2'log3=y. nilai 12'log 60=

12'log 60 =  \frac{c^log60}{c^log12} 

karena di soal 2'log 5= X DAN 2'log3=y maka kita pilih 2 utk c nya

12'log 60 =  \frac{2^log60}{2^log12} 
 =\frac{2^log5.3.4}{2^log4.3} 
 =\frac{2^log5.2^log3.2^log4}{2^log4.2^log3} 
 =\frac{x.y.2}{2.y} 
 =x