k/(k-k-2)(k-2)=10 lanjutannya gimana ya

Materi Aljabar
[tex] \displaystyle \frac{k}{(k-k-2)(k-2)} = 10 \\ \frac{k}{(-2)(k-2)} = 10 \\ k = 10(-2k+4) \\ k = -20k + 40 \\ 21k = 40 \\ k = \frac{40}{21} [/tex]