Matematika

Pertanyaan

integral. batuin ya teman teman. butuh banget
integral.  batuin ya teman teman. butuh banget

1 Jawaban

  • Nomer 8
    b. F'(x) = 6x² - 2x + 5 , F(0) = 5
    >> F(x) = (6/3)x³ - (2/2)x² + 5x + C
    >> F(0) = 0 - 0 + 0 + C = 5  >>>>>> C=5
    >> F(2) = 2(2³) - 2² +5(2) + 5
                 = 16 - 4 + 10 + 5
                 = 27

    c. F'(x) = 1/2x² , F(3) = 7/6
    >> F(x) = (1/2)(-1)/x + C
    >> F(3) = -1/6 + C = 7/6   >>>>>>>>> C=8/6
    >> F(2) = -1/4 + 8/6
                = -3/12 + 16/12 = 13/12

    d.  F'(x) = 2(6x² - 1) , F(0)=5 dan F(1)=2 (ini kayanya ada yang salah sama soalnya) (tapi kalo mau tetap dihitung juga F(2) nya, iya hitung aja sesuai nilai C nya.
    >> F(x) = 2(2x³ - x) + C
    >> F(0) = 2(0 -0) + C = 5 >>>>>>>>>> C = 5
    >> F(1) = 2(2 - 1) + C = 2 >>>>>>>>> C = 0

    >> F(2) = 2(2(2³) - 2) + 5 = 31
    >> F(2) = 2(2(2³) - 2)  + 0 = 28