integral ³√1/2x-5 dx

InTegraL

Misal :
u = 1/2 x - 5
du/dx = 1/2
dx = 2 du

∫ax^n dx = a/(n+1) . x^(n+1) + C

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∫³√(1/2 x - 5) dx
= ∫u^(1/3) . 2 du
= 2/(4/3) . u^(4/3) + C
= 3/2 u ³√u + C
= 3/2 (1/2 x - 5) ³√(1/2 x - 5) + C