Matematika

Pertanyaan

Jika 49log (2log(6x+2))=1/2, nilai x=???

1 Jawaban

  • LogAritMa

    49'log (2'log (6x + 2)) = 1/2
    2'log (6x + 2) = 49^1/2
    2'log (6x + 2) = 7
    6x + 2 = 2^7
    6x = 128 - 2
    6x = 126
    x = 21

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