Jika 49log (2log(6x+2))=1/2, nilai x=???
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Jika 49log (2log(6x+2))=1/2, nilai x=???
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1. Jawaban Anonyme
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49'log (2'log (6x + 2)) = 1/2
2'log (6x + 2) = 49^1/2
2'log (6x + 2) = 7
6x + 2 = 2^7
6x = 128 - 2
6x = 126
x = 21