penyelesaian dari persamaan |2×+4|+8=14 adalah

Materi : Nilai Mutlak
kelas : X SMA

I2x + 4I + 8 = 14
I2x + 4I = 14 - 8
I2x + 4I = 6
2x + 4 = 6 atau -6

2x + 4 = 6
2x = 6 - 4
2x = 2
x = 1

2x + 4 = -6
2x = -6 - 4
2x = -10
x = -5

Hp = {-5 , 1 }

|2x+4|+8 = 14
2x + 4 + 8 = 14
2x + 12 = 14
2x = 14 - 12
2x = 2
x = 1