An object has a position equation of 2t²+4t-8 the equation of the velocity sector for the object is
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An object has a position equation of 2t²+4t-8 the equation of the velocity sector for the object is
1 Jawaban
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1. Jawaban Anonyme
Kinematics.
x = 2t² + 4t - 8
v = dx / dt
= 4t + 4