Matematika

Pertanyaan

tolong ya kk.. nomer 1 dan 2
tolong ya kk.. nomer 1 dan 2

2 Jawaban

  • 1. a.
    BD² = AD x CD
    4² = 2√5 x CD
    16 = 2√5 x CD
    CD = 16 / 2√5
    CD = 16√5 / 10
    CD = 8√5 / 5 cm

    1.b
    BC² = CD x AC
    BC² = 8√5 / 5 x (2√5 + 8√5 / 5)
    BC² = 8√5 / 5 x 18√5 / 5
    BC² = 144/5
    BC = √144/5
    BC = 12√5 / 5 cm

    1.c.
    AB² = AD x AC
    AB² = 2√5 x 18√5 / 5
    AB² = 36
    AB = √36
    AB = 6 cm

    1.d.
    AC = AD + CD
    AC = 2√5 + 8√5 / 5
    AC = 18√5 / 5 cm

    2.
    EF / DE = BC / AB
    EF / 12 = 20 / 18
    EF / 12 = 10/9
    EF = 10/9 x 12
    EF = 40/3 cm

    DF / DE = AC / AB
    DF / 12 = 24 / 18
    DF / 12 = 4/3
    DF = 4/3 x 12
    DF = 16 cm
  • 1)
    AD = 2V5 cm
    BD = 4 cm
    a) CD
    b) BC
    c) AB
    d) AC

    a)
    (BD)^2 = AD × CD
    4^2 = 2V5 × CD
    16 = 2V5 × CD
    CD = 16/(2V5)
    CD = [16/(2V5)] × [(2V5)/(2V5)]
    CD = (32V5)/20
    CD = (8V5)/5 cm

    b)
    (BC)^2 = CD × CA
    (BC)^2 = (8V5)/5 × [(8V5)/5 + (2V5)]
    (BC)^2 = (8V5)/5 × [(8V5)/5 + (10V5)/5]
    (BC)^2 = (8V5)/5 × (18V5)/5
    (BC)^2 = 720/25
    (BC)^2 = 144/5
    BC = V(144/5)
    BC = 12/V5
    BC = (12/V5) × (V5 × V5)
    BC = (12V5)/5 cm

    c)
    (AB)^2 = AD × AC
    (AB)^2 = 2V5 × (18V5)/5
    (AB)^2 = 36
    AB = V36
    AB = 6 cm

    d)
    AC = AD + CD
    AC = 2V5 + (8V5)/5
    AC = (10V5)/5 + (8V5)/5
    AC = (18V5)/5 cm


    2)
    a)
    EF/BC = DE/AB
    EF/20 = 12/18
    EF × 18 = 12 × 20
    18EF = 240
    EF = 240/18
    EF = 13 6/18
    EF = 13 1/3 cm

    b)
    DF/AC = DE/AB
    DF/24 = 12/18
    DF × 18 = 12 × 24
    18DF = 288
    DF = 288/18
    DF = 16 cm