persamaan linear satu variabel dari 2x - 4 = 8 -4 + 3s = 24 -8 - d2 = 32 5(u - 2) =u - 2 2x - 1 + 5 -3 = x x2 + 7 = 9 5,2 -7x + 0 3 + x3 - x = 4 10 = x +6
Matematika
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Pertanyaan
persamaan linear satu variabel dari
2x - 4 = 8
-4 + 3s = 24
-8 - d2 = 32
5(u - 2) =u - 2
2x - 1 + 5
-3 = x
x2 + 7 = 9
5,2 -7x + 0
3 + x3 - x = 4
10 = x +6
2x - 4 = 8
-4 + 3s = 24
-8 - d2 = 32
5(u - 2) =u - 2
2x - 1 + 5
-3 = x
x2 + 7 = 9
5,2 -7x + 0
3 + x3 - x = 4
10 = x +6
1 Jawaban
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1. Jawaban Yunarni251
2x - 4 = 8
2x = 8 + 4
2x = 12
x = 6
-4 + 3s = 24
3s = 24 + 4
3s = 28
s = 9 1/3
-8 - d2 = 32
d2 = -32 - 8
d2 = -40
d = √40
d = √4 × √10
d = 2 × √10
d = 2√10
5(u - 2) =u - 2
5u - 10 = u - 2
5u - u = -2 + 10
4u = 8
u = 2
2x - 1 + 5 (kurang tau)
2x + 4
-3 = x
x = -3
x2 + 7 = 9
x2 = 9 - 7
x2 = 2
x = √2
5,2 -7x + 0 (kurang tau)
3 + x3 - x = 4 ( kurang tau)
10 = x +6
-x = - 10 + 6
-x = - 4
x = 4
itu jwabannya