integral (6x-3 ) akar 2x-1 dx

InTegraL

Misal :
u = 2x - 1
du/dx = 2
dx = 1/2 du

∫(6x - 3)√(2x - 1) dx
= 3 ∫(2x - 1)√(2x - 1) dx
= 3 ∫(2x - 1)^3/2 dx
= 3 ∫u^3/2 . 1/2 du
= 3/2 . 1/(5/2) . u^5/2 + C
= 3/5 u² √u + C
= 3/5 (2x - 1)² √(2x - 1) + C