F(x)=x²+bx+14 memiliki sumbu simetri X1=-3 Nilai minimuk F(x) adalah

Bab Fungsi Kuadrat
Matematika SMP Kelas VIII

f(x) = x² + bx + 14
a = 1; b = b; c = 14

sumbu simetri = -3
              -b/2a = -3
              -b/(2 . 1) = -3
              -b = -3 . 2
              b = 6

f(x) = x² + 6x + 14
f(-3) = (-3)² + 6 . (-3) + 14
        = 9 - 18 + 14
        = 5