2CuCI(s) --> 2Cu(s)+CI(g) deltaH = +274,4 kj/mol 2CuCI(s) + CI2(g) --> 2CuCI2(s) deltaH = -165,8 kj/mol DeltaH untuk reaksi Cu(s)+CI2(g) --> CuCI2(s)??
Kimia
Sandibkc31
Pertanyaan
2CuCI(s) --> 2Cu(s)+CI(g) deltaH = +274,4 kj/mol
2CuCI(s) + CI2(g) --> 2CuCI2(s) deltaH = -165,8 kj/mol
DeltaH untuk reaksi Cu(s)+CI2(g) --> CuCI2(s)??
2CuCI(s) + CI2(g) --> 2CuCI2(s) deltaH = -165,8 kj/mol
DeltaH untuk reaksi Cu(s)+CI2(g) --> CuCI2(s)??
1 Jawaban
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1. Jawaban sintariyusuf
(1) 2CuCI(s) --> 2Cu(s)+CI2(g) ∆H = +274,4 kj/mol
(2) 2CuCI(s) + CI2(g) --> 2CuCI2(s) ∆H = -165,8 kj/mol
∆H untuk reaksi Cu(s)+CI2(g) --> CuCI2(s)
-reaksi 2 tetap dan dibagi 2
-reaksi 1 dibalik dan dibagi 2
(1). Cu + 1/2Cl2=> CuCl ∆H= -137.2
(2). CuCl + 1/2Cl2 => CuCl2 ∆H =-82.9
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Cu + Cl2 =>CuCl2 ∆H= -220.1