Matematika

Pertanyaan

(½ log 3 + ¼ log 9) (³log 1/4 +9 log 1/2 )

1 Jawaban

  • LogAritMa

    [(½)'log 3 + (¼)'log 9] [³log ¼ + 9'log ½]
    = (½)'log (3 × 9^½) × ³log (¼ . (½)^½)
    = (½)'log 3² × ³log (½)^(5/2)
    = 2 × 5/2
    = 5 ✔

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