Melalui titik A (3,-3) dan tegak lurus garis 2x-2y+6 = 0 adalah....... Pleasee bangett dibantuu Thanks:)

Bab Persamaan Garis
Matematika SMP Kelas VIII

ax + by + c = 0, tegak lurus, (p, q)
bx - ay - (b .p - a . q) = 0

2x - 2y + 6 = 0, tegak lurus, (3. -3)
-2x - 2y - (-2 . 3 - 2 . (-3)) = 0
-2x - 2y - (-6 + 6) = 0
-2x - 2y = 0
2x + 2y = 0