|x+1|pangkat 2+2|x+2|>2

|x+1|² + 2|x+2| > 2
= (x+1)² + 2(x+2) > 2
= x²+2x+1 + 2x+4 > 2
= x²+2x+2x+1+4 > 2
= x²+4x+5 > 2
= x²+4x+5-2 > 0
= x²+4x-3 > 0
= (x+1)(x+3) > 0
= x : -1, -3
= x < -3
-3 < x < -1
x > -1
= x < -3 atau x > -1

Semoga membantu ya ^_^
Maaf kalau salah.